How can I change is output format by awk ?

Shell Programming and Scripting
1

Hello,
Can you tell me how can I change this format by awk

Input

0.2057422D-01  
0.2463722D-01
-0.1068047D-02

Output

0.02057422
0.02463722
-0.001068047

Thanks
wan

2 
 awk -FD '{print $1}' file_name
3 
sed 's/D-.*//' Input

Maybe it makes it easier for someone to "translate" it in awk...
Edit: sorry, I did not see that extra zeros :rolleyes:

4

thank you
i try to use this command

awk -FD '{print $1}' file_name

and my output is

0.2057422
0.2463722
-0.1068047

But i want this form

0.02057422
0.02463722
-0.001068047

How can i change is form by using awk
thank you very much
wan

5

what is the logic in your output ?

6

I'm out... :rolleyes:

7

thanks for the reply
I just want to change
From

0.2057422D-01

To

0.022057422

by using awk
Any other idea?

Thanks for this

8

Your question is becoming increasingly incoherent. Originally you asked how to divide a number by 10, or by 100, then your desired output was not only in a different format, but not even the same number in any format!!

awk '{ print $1+0 }' file

or

awk '{ printf( "%.7f\n"), $1 }'
9

Hi.

My take on this is that a number like 0.2057422D-01 is not recognized as the double-precision equivalent of 0.2057422E-01, i.e. scientific notation, but from a code which produces the "D" to signify a double-precision result. An example of such a code might be Fortran.

An awk rule like:

{ sub(/D/,"E",$1) ; printf( "%.8f\n"), $1 }

for the input:

0.2057422D-01  
0.2463722D-01
-0.1068047D-02

would produce:

0.02057422
0.02463722
-0.00106805

which is rounded for the last number, but produces essentially what the OP desires ... cheers, drl