help understanding regex with grep & sed

Shell Programming and Scripting
1

I have the following line of code that works wonders. I just don't completely understand it as I am just starting to learn regex. Can you help me understand exactly what is happening here?

find .  -type f | grep -v '^\.$' | sed 's!\.\/!!'
2

Here is what it is doing:-

find .  -type f

Finds all the files in a directory

grep -v '^\.$'

Removes files starting with . and also ending with . (since you are using -type f, this is not necessary)

sed 's!\.\/!!'

Removes first occurence of ./ from the output.

3

That actually means find all files recursively down the tree rooted at the current directory.

4

Thanks. I knew what

find . -type f

was for, but it was part of the line of code, so I kept it in. Thanks again for explaining the regex part!

5

You can shorten the command to:

find .  -type f  | sed 's!./!!'