Grep/awk part of info of a column

Shell Programming and Scripting
1

I have a question that I am at a loss to solve. I have 3 column tab-separated data, such as:

abs nmod+n+n-commitment-n   349.200023 
abs nmod+n+n-a-commitment-n 333.306429 
abs into+ns-j+vn-pass-rb-divide-v   295.57316 
abs nmod+n+ns-commitment-n  182.085018 
abs nmod+n+n-pledge-n   149.927391
abs nmod+n+ns-reagent-n 142.347358

I need to isolate the last two "elements" of the third column, in which my desired result would be a 4-column output that only contains those elements that end with "-n".
such as:

abs nmod+n+n   commitment-n   349.200023
abs nmod+n+n-a   commitment-n 333.306429 
abs nmod+n+ns   commitment-n  182.085018 
abs nmod+n+n   pledge-n   149.927391
 abs nmod+n+ns   reagent-n 142.347358

.

In this case, is there an awk, grep anything that can help? The files are approx. 500 MB, so they are not huge, but not small either. Thanks for any insight.

2

Try

awk '$2~/-n$/ {sub (/-/," ", $2); print}' file
abs nmod+n+n commitment-n 349.200023
abs nmod+n+n a-commitment-n 333.306429
abs nmod+n+ns commitment-n 182.085018
abs nmod+n+n pledge-n 149.927391
abs nmod+n+ns reagent-n 142.347358

EDIT: I see an error in line 2. Let me think...

---------- Post updated at 12:55 ---------- Previous update was at 12:38 ----------

This may be more adequate:

 awk '$2~/-n$/ {sub (/-[^-]*-n$/," &", $2); $0=$0; sub (/^-/,"",$3); print}' file
abs nmod+n+n commitment-n 349.200023
abs nmod+n+n-a commitment-n 333.306429
abs nmod+n+ns commitment-n 182.085018
abs nmod+n+n pledge-n 149.927391
abs nmod+n+ns reagent-n 142.347358
1 Like
3

Try :

$ awk '$2~/-n$/{j=0;for(i=length($2);i>=1;i--){if(substr($2,i,1)~/\-/){++j}if(j>1)break};$2 = substr($2,1,i-1) FS substr($2,i+1);print}' file

abs nmod+n+n commitment-n 349.200023
abs nmod+n+n-a commitment-n 333.306429
abs nmod+n+ns commitment-n 182.085018
abs nmod+n+n pledge-n 149.927391
abs nmod+n+ns reagent-n 142.347358