Grep with multiple instances of same pattern

Shell Programming and Scripting
1

Hi,

This is my text file I'm trying to Grep.

Apple Location Greenland Rdsds dsds fdfd ddsads http Received Return Immediately Received End

My Grep command:

grep only--matching 'Location.*Received'

Because the keyword Received appears twice, the Grep command will stop at the last one:
Location Greenland Rdsds dsds fdfd ddsads http Received Return Immediately Received

I want it to stop after the first one:
Location Greenland Rdsds dsds fdfd ddsads http Received

How is that possible?

Thanks

2

With awk ...perhaps a solution...

cat file | awk -F "Received" '{print $1,"Received"}'

3

I don't believe grep is intended to do such a thing, but something like this

perl -pe 's/.*(Location.*?Received).*/$1/' your_file

can.

edit:
Well i was wrong: grep could, though
man grep says -P --perl-regexp
Interpret PATTERN as a Perl regular expression. This is highly experimental and grep -P may warn of unimplemented features

and in deed, Debian GNU/Linux says:
grep: Support for the -P option is not compiled into this --disable-perl-regexp binary

4

thanks man, it works!