[grep] how to grep a sentence which has quotation marks "sentence"

Shell Programming and Scripting
1

I would like to check with grep in this configuration file:

{
"alt-speed-down": 200,
"alt-speed-enabled": true,
"alt-speed-time-begin": 1140,
"alt-speed-time-day": 127,
"...something..." : true,
...
}
"alt-speed-enabled" (the third line of the file) is setted to true. I have tried this:

if grep ""alt-speed-enabled": false" /home/ciro314/.config/transmission/settings.json -c; then
          zenity --info --text "MESSAGE" &
fi

it does not work because of the "" . Could anybody helpme, please?

2

how about

grep 'alt-speed-enabled' filename | grep -q 'true' && ok=1 || ok=0
if [ $ok -eq 1 ]; then
  zenity -- and so on
fi

you can also use a regular expression in a single grep -q command, but I thought this one would be easier to understand.

3

Or

if grep -q '"alt-speed-enabled":.*false' infile; then
  zenity blabla...
fi