Grep for a line containing only 5 numbers

UNIX for Advanced & Expert Users
1

How would you grep for a line containing only 5 numbers? Something like this.

       10      2       12      1       13
2

Hi Cokedude,

Question was not clear.
Could explain more precisely....

---------- Post updated at 06:54 AM ---------- Previous update was at 06:49 AM ----------

Try this

grep "10  2  12  1  13" filename
3 
awk 'NF==5 {for (i=1;i<=NF;i++) if ($i !~ /^[0-9]*$/) x=1; if (!x) print; x=""}' file
4

Perhaps a bit more generic:

grep "[[:space:]]*10"[[:space:]]*2"[[:space:]]*12"[[:space:]]*1"[[:space:]]*13" file4
       10      2       12      1       13
5 
 echo "       10      2       12      1       13" | grep "^[ \t]*\d\+[ \t]*\d\+[ \t]*\d\+[ \t]*\d\+[ \t]*\d\+[ \t]*$"