Grep Command

Shell Programming and Scripting
1

I have one text file, contains some values like <Q1:Name>1000000</Q1:Name>. I want to read the values and stores into an array for searching the each values into a file locations.
If I use this

find location |xargs grep -l "<Q1:Location>100000055042</Q1:Location>"

,I get the files, are having that value but if I store the values into an array and use the same command

find location |xargs grep -l "${array[$i]}"

it couldn't find the files. it's showing find: bad status-- location
Can you please tell me what is the problem?

2

Which shell are you using? sh, csh, bash?

3

bash shell.

4

Can you paste the relevant part of the script i.e. array population, actual file contents being used etc

--ahamed

5

How are you

What command(s) are you using to do this?

6

PFA the file,script. want to delete the files,hav the match values from that location.

7

You may want to paste the commands to a message, as well as a small section of the data.
Many, myself included, do not open zipped files.

8

File contains the values like this:

LOC
<Q1:Location>100000035647</Q1:Location>
<Q1:Location>012010087120</Q1:Location>
<Q1:Location>100000057069</Q1:Location>
<Q1:Location>9500023238</Q1:Location>
<Q1:Location>9001013233</Q1:Location>
<Q1:Location>9001017224</Q1:Location>
<Q1:Location>100000055042</Q1:Location>
<Q1:Location>100000193712</Q1:Location>

Code in script

index=0
while read LOC
do
[ "$LOC" == "LOC" ] && continue 
Service[$index]=$LOC
echo ${ServiceNonProd[$index]}
find location |xargs grep -l "${Service[$index]}"|xargs rm -r 
index=`expr $index + 1`
done < location/Target.txt