getting value between double quote

Shell Programming and Scripting
1

Can somebody supply me with a simple way to get a value between
two double quotes?

Example:

input =  ADR base is "/u01/app/oracle"

output  = /u01/app/oracle

Thanks to all who answer

2 
awk -F\" '{print $2}' inputfile
1 Like
3 
$
$
$ cat data.txt
ADR base is "/u01/app/oracle"
$
$
$ cut -d'"' -f2 data.txt
/u01/app/oracle
$
$

tyler_durden

5 
% s='ADR base is "/u01/app/oracle"'
% expr "$s" : '.*"\([^"]*\)"'
/u01/app/oracle
6 
inp='ADR base is "/u01/app/oracle"'
eval set -- $inp
eval echo \$$#