Formatting ls output

Shell Programming and Scripting
1

I am using find and ls to search for "warez" files on my server.

find /home/ -regex ".*\.\(avi\|mp3\|mpeg\|mpg\|iso\)" -print0 | xargs -0 ls -oh

This command produces this:

-rw-r--r-- 1 1000 3.2M Feb 18 2009 /home/user/public_html/lupus.mp3

I want to only get this

3.2M /home/user/public_html/lupus.mp3

Or even better, this output:

/home/user/public_html/lupus.mp3 | 3.2M

Would like to have some input on how to solve this problem, thanks

2

Try:

find /home -regex ".*\.\(avi\|mp3\|mpeg\|mpg\|iso\)" -exec ls -sh {} \;

find /home -regex ".*\.\(avi\|mp3\|mpeg\|mpg\|iso\)" -exec ls -sh {} \; |awk '{print $2" | "$1}'
3

Pipe it to awk and print whatever fields you want in whatver order.

| awk ' | awk '{print $8 $4}'
4

it works, but it cannot handle filenames with whitespaces.

/usr/bin/time -o /tmp/time.txt -f %E find /home/ -regex ".*\.\(avi\|mp3\|mpeg\|mpg\|iso\|rar\)" -exec ls -sh {} \; |awk '{print $2" | "$1}' > /tmp/result.txt

It works until awk gets involved, when printing $2 the whitespaces gets lost.

5 
/usr/bin/time -o /tmp/time.txt -f %E find /home/ -regex ".*\.\(avi\|mp3\|mpeg\|mpg\|iso\|rar\)" -exec ls -sh {} \; |sed 's/ /|/' |awk 'BEGIN{FS=OFS="|"} {print $2,$1}'