For loop not working

Shell Programming and Scripting
1

Hi All,

For loop in ksh not working if it was given in the following method.

simple script:

for i in {1..4}
do
echo $i
done

Output:

{1..4}

Even below also not working :frowning:

Script:

for (( c=1; c<=5; c++ )) do 	echo "Welcome $c times..." done

Output:

./x.sh: 0403-057 Syntax error at line 1 : `(' is not expected

Please help me out :frowning:

2

What system do you use? Where are you try your loops - on the command line? Or in a script and what is the first line of your script in this case?

3

Still getting the same error :confused::confused:

./x.sh: 0403-057 Syntax error at line 1 : `(' is not expected.
4

He or she probably using older version of KSH.
In KSH93 it should work fine.

Try this to accomplish the same thing in current ksh :

a=1
while [ $a -le 5 ]; do
echo $i
((a+=1))
done
5

"Still getting the same error" without answering any of yazus questions doesn't tell us anything. It's like telling the doctor "It's still hurting" when being asked where it hurts.

6

sorry for that :), wrongly copied.

AIX-P550, i'm trying to execute the for loop in script.

#!/usr/bin/ksh is the first line

Thanks

7

That's my fault. I corrected my post. I was fast, but girish_satyam was faster. :slight_smile:
Sorry but I know almost nothing about AIX.

8

Can you try the below one..?

#!/usr/bin/ksh 
for i in $(seq 1 4)
do
	echo $i
done
9

After execution getting the below error now :frowning:

#!/usr/bin/ksh for i in $(seq 1 4) do echo $i done
Output:
./x.sh[2]: seq: not found.

10

Then you would need this..if its ok for you.

#!/usr/bin/ksh 
for i in 1 2 3 4
do
	echo $i
done
11

#!/usr/bin/ksh for i in 1 2 3 4 do echo $i done
I have already tried the above, it works fine but in for loop declaration i should pass a variable, i cannot use static count :frowning:

$count should be the last value, for i in {1..$count} [i feel as 'Peasant' said my shell version is 5.2]

kindly excuse me for asking second question in the same topic
Michael, issue regd the variable declaration using 'eval'
As suggested by you i have done the below and working fine....

eval gmp${count}=${i}
eval echo \$gmp${count}

----failing at below point, the varibale 'oname' not storing the result :wall::wall:---
eval oname=eval echo \$gm${count}

Please guide me, thanks in advance :slight_smile:

12

Since your just storing the output in a variable below one is enough..

oname=$(eval echo \$gmp${count})
13

Hi Michael,

thanks for that :), its working the variable issue.

Can you please suggest me any solution for the 'for loop' too ? :(:smiley:

14 
n=4
for i in `awk -vn=$n 'BEGIN {for (i=1; i<=n; i++) print i}'`; do         
  echo $i
done

Or, if this doesn't work try to use nawk.