FINDING DUPLICATE PROJECT ( directory project )

Shell Programming and Scripting
1

I have a project tree like that.

after running find command with the -no -empty option, i am able to have a list of non empty directory

    DO_MY_SEARCH="find .    -type d -not -empty -print0"
MY_EXCLUDE_DIR1="  -e NOT_IN_USE -e RTMAP -e NOT_USEFULL   "
echo " " > $MY_TEMP_RESULT_1
while IFS= read -r -d '' file; do
        CURRENT_DATA=$file
        echo $CURRENT_DATA | grep -v ${MY_EXCLUDE_DIR1} >> $MY_TEMP_RESULT_1
    done < <($DO_MY_SEARCH)

I have some duplicate project :

1 : project some_project
/dir_a/dir_1/dir_1-2/dir_1-2-1/dir_1-2-1-1/some_project
and
/dir_a/dir_1/dir_1-4/some_project
and
/dir_a/dir_4/dir_4-1/dir_4-1-1/dir_4-1-1-1/some_project

2 : project dir_1-3-2-1-1
/dir_a/dir_1/dir_1-3/dir_1-3-2/dir_1-3-2-1/dir_1-3-2-1-1
and
/dir_a/dir_7/dir_7-1/dir_7-1-1/dir_7-1-1-1/dir_7-1-1-1-1/dir_1-3-2-1-1

3 : project another_project
/dir_a/dir_6/dir_6-1/another_project
and
/dir/a/dir_8/another_project

How to get the duplicate leaf name :
some_project
dir_1-3-2-1-1
another_project

Any help is welcome.

2

How about

while read PROJ; do PROJ=${PROJ##*/}; echo $PROJ; done < $MY_TEMP_RESULT_1 | sort | uniq -d
another_project
dir_1-3-2-1-1
some_project
1 Like
3

seems to work on a real example.
As the real problem is more complicated, this give me the way to finish by hand.

Thank you very much