Find files of particular day

Hi,

I need to find all files of particular day lets say for 2nd august in below.

-rw-r--r--   1 skl  eusdc       8168 Aug  5 19:31    aabc123.txt
-rw-r--r--   1 skl  eusdc       4251 Aug  5 19:31    aabc124.txt
-rw-r--r--   1 skl  eusdc       4252 Aug  6 19:31    aabc125.txt
-rw-r--r--   1 skl  eusdc       3895 Aug  6 19:31    aabc213.txt
-rw-r--r--   1 skl  eusdc       3896 Aug  2 19:31    aabc456.txt
-rw-r--r--   1 skl  eusdc       3183 Aug  2 19:31    aabc63453.txt
-rw-r--r--   1 skl  eusdc       3184 Aug  2 19:31    aabcqwe.txt
-rw-r--r--   1 skl  eusdc       1047 Aug  3 07:30    mnbvcc.txt
-rw-r--r--   1 skl  eusdc       1048 Aug  3 07:30    as54633.txt
-rw-r--r--   1 skl  eusdc       1047 Aug  3 07:30    poiuy78.txt
-rw-r--r--   1 skl  eusdc       1048 Aug  3 07:30    sdfsd.doc
-rw-r--r--   1 skl  eusdc      10596 Aug  3 07:30   dfgd.txt
-rw-r--r--   1 skl  eusdc      10600 Aug  3 07:30   qweqw.doc

grep " Aug 2 " inputfile

i need to find all files of lets say Aug 2 and the counts for a particular string lets say "abc" is present in the files received for Aug 2

How about:

ls -ld *abc* | grep "Aug  2"

It just give me files of Aug 3. How about finding the total count of a string lets say "sachin" in all the files of Aug 3

Try

$ ls -l | awk '/Aug  2/ { print $NF }' | grep -c 'sachin'

It still does not answer my question. It looks for string 'sachin' in the filenames which is i dont want. I need to find total count of string 'sachin' in the text present inside the files not in the filenames.

$ ls -l | awk '/Aug  2/ { print $NF }' | xargs grep -c 'sachin'

Or

$ for f in $(ls -l | awk '/Aug  2/ { print $NF }'); do grep -c 'sachin' $f; done

OR

 grep "sachin" `ls -ltr | grep " Aug 2 " | awk '{print $9}'`

ls -l | awk '/Aug 2/ { print $NF }' | xargs grep -c 'sachin' | awk -F ":" '{ total += $2 } END {print total}';

Hi Pravin..

I tried what u said but it gives me the below error:

awk: syntax error near line 1
awk: bailing out near line 1
$ xargs: Child killed with signal 13

It's running fine for me. You can try another one.

total=0;for f in $(ls -l | awk '/Jun 22/ { print $NF }'); do cnt=`grep -c 'pravin' $f` total=`expr $cnt + $total`;done ; echo $total

If you are on Solaris, try "nawk" not "awk".

Pls try this..

ls -l | grep "Aug  2" | awk '{print $8}' | xargs -iVAR grep -i sachin VAR | wc -l

This is the perfect answer that i was looking for. Great job Rajamadhavan:b: