filtering the log file

Shell Programming and Scripting
1

Hi i have a log file like example below.

I need only one field from below log [8AC1178C859113944F130797425349430] all other need to be truncated from the log file.

2011-06-13 15:10:53,498 INFO [8AC1178C859113944F130797425349430] [com.tmobile.ei.sbp.cal.logging.LMSHelper] ext.SP->CAL (log point 5)

can any body help on this please.

Thanks

2 
cut -d\[  -f2 <file.log| cut -d \] -f1
OR 
awk -F'\[' '{print "["$2}' file.log

Update Doh, Corona's solution below is much neater, though the cut could be updated to

cut -d\  -f4 <file.log
3

awk '{ print $4; }' < filename

4

Like this?

sed 's/.* \(\[[^ .]*\]\) .*/\1/' logfile

This will grab the field in brackets with no spaces or dots inside.

5

This one works like a charm.. is there any output will send to another file.

Thank you very much.

---------- Post updated at 10:52 AM ---------- Previous update was at 10:39 AM ----------

Thanks
I have moved output to file using redirection.... >>