filesystems > 70%

Shell Programming and Scripting
1

I need a scrip that will show me the filesystems that are greater than 70%...but not sure how to filter using the df -h | grep

Thank you for your help!!

2

Grep doesn't understand numerals. Doing that in grep would be awkward at best.

In any case we don't know what your df -h output looks like. It's not the same everywhere.

3

This is just an example of what it looks like..

Filesystem            Size  Used Avail Use% Mounted on
/dev/mapper/rootvg-rootlv
                      5.0G  3.3G  1.4G  71% /
tmpfs                 4.0K     0  4.0K   0% /dev/vx
/dev/cciss/c0d0p1     251M   87M  152M  37% /boot
none                  7.9G     0  7.9G   0% /dev/shm
/dev/mapper/rootvg-homelv
                     1008M   34M  923M   4% /home
/dev/mapper/rootvg-optlv
                      2.0G 1021M  894M  54% /opt
/dev/mapper/rootvg-tmplv
                      3.0G  473M  2.4G  17% /tmp
4

How about this

 
df -h | perl -ne 'print if (/(\d+)%/ && $1>70)'
1 Like
5

Something like this:

 
df -h | awk 'NR == 1 { print ; next }
NF==6 { gsub("%",""); if ($5 > 35)  print ;next }
NF==1 { gsub(" ",""); a=$0;next}
{ gsub("%",""); $1=$1; if ($4 > 35)  print a" "$0 }'
1 Like
6 
df -h|nawk '{gsub(/%/,"");if($5>70)print}'

Thanks
Sha

1 Like
7 
df -h|nawk 'int($5)>70'