File Watcher Help !!

Shell Programming and Scripting
1

Hi Experts
I will have be having 3 types of files in directory
file1_p0_date
file1_p1_date
file1_p2_date
As soon as it sees any of the files it needs to kick off another process and also would need the file name
For this I am creating a file watcher script which will look for file1* My questions are :
1) how to get the file name ?
2) After it gets the first file and Kicks off the process will I have to delete the file or move it to another directory so that it does not pick the same again?
Thanks for the help

2

This doesn't check if the file transfer has completed etc. But should be enough to get you started?

#!/bin/ksh 

if [ ! -d .done ] ; then
    mkdir .done
fi

if [ ! -d .error ] ; then
    mkdir .error
fi

while true
do
    file_list=$( ls file1_* 2>/dev/null )
    if [ -n "$file_list" ] ; then
        for file_name in $file_list ; do
            echo "Processing $file_name"
            #run some command...
            if [ $? -eq 0 ] ; then
                mv $file_name .done/ # Assume .done dir
            else
                mv $file_name .error/ # Assume .error dir
            fi
        done
    fi
    sleep 2
done
3

Thanks a lot for your prompt reply Rakesh !!
Will try this out

Thanks
Bob