Hi
I'm using the below command in shell script to check for file exists in the path
if [ ! -r $path/$test.csv ]
.....
fi
path and test are variables
path and the file exists but the commands inside if condition is executed (! operator used)
Is the above way of checking for file existence is correct?
Thanks
zaxxon
July 20, 2011, 10:54am
2
if [[ -e $path/$test.csv ]]; then
...
fi
Check the man page for test
to see your option for switches.
1 Like
try this:
path=/home/something
filename=nameof_file
completepath=$path/$filename
if [ ! -r $completepath ] ; then
echo "NOT exits"
else
echo "Exists"
fi
Thanks it works
I have another question. Declared a variable like test="../path"
Referring the variable as $test/file_name.txt
Where does the directory 'path' needs to be created in the current directory? exists but still errors and in the directory before also exists
what does .. refers to?
zaxxon
July 20, 2011, 11:18am
5
..
refers to the next upper level of the current directory structure. When you have a script that is being executed from any path, it might be safer to use absolute paths instead.
1 Like