Fgrep/grep -f and literal strings

Shell Programming and Scripting
1

I have a file like this:

cat file

name = server
jobname = 1010
snapshot_name = funky_Win2k12_20140213210409

I'm trying to use grep to isolate that first line (name = server), but

grep -f  "name = " file

as well as

fgrep "name = " file

returns all 3 lines. How do I return results LITERALLY as I'm quoting them without it including matches that have preceding text?

---------- Post updated at 03:17 PM ---------- Previous update was at 03:11 PM ----------
*Edit - Might've answered my own question....seems that '^' works.

i.e. -

grep "^name = " file
2

Hi.

Assume z4 contains:

name = server
jobname = 1010
snapshot_name = funky_Win2k12_20140213210409

then:

$ fgrep -w "name =" z4
name = server

For:

OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian 5.0.8 (lenny, workstation) 
fgrep GNU grep 2.5.3

See man fgrep for details.

Best wishes ... cheers, drl