Hi
I am trying to create a script extracting the IP provided by ifconfig.
I tried with grep + awk but I am returned more than I need.
/sbin/ifconfig eth0 | grep "inet addr:" | awk '/inet addr:/ { print $2 }'
and returns
addr:10.15.1.64
How can I remove "addr:" string?
Thanks in advance
A bit modification :
/sbin/ifconfig eth0 | awk -F":" '/inet addr:/ { print $2 }'
/sbin/ifconfig eth0 | grep "inet addr:" | awk '/inet addr:/ { print $2 }' | cut -d":" -f2
or
/sbin/ifconfig eth0 | grep "inet addr:" | awk '/inet addr:/ { print $2 }' | awf -F":" '{print $2}'
Depending ifconfig's o/p this should also work:
ifconfig eth0 | awk -F":| +" '/inet adr/{print $4}'
If it doesn't work, post ifconfig's o/p.
Using grep and cut with awk is redundant but piping the result of an awk output to awk is ...
:rolleyes:
$ ifconfig eth0 | perl -ne 'if ( /inet addr:(^\s]+)/) { print $1; }'
Using Perl:
/sbin/ifconfig eth0 | perl -lne '/inet addr:([\d.]+)/ && print $1'
tyler_durden
Thank you all for your solution!
It works great!
Mn
ifconfig eth0|sed -n 's/^.*inet addr:\([0-9.]*\).*/\1/p'