extract csv based on column value

Shell Programming and Scripting
1

Hi I have a csv file which is below

A,5
B,6
C,10
D,7

I want the values who's second column is greater than 7
say

C,10
D,7

Help me please...
Thanks,
Maruth

2

Something like this?

awk -F, '$2>=7' file
3

greater than or equal according to your output I guess:

#  awk -F"," '$2>=7' infile
C,10
D,7

HTH

4

Thanks a lot... It worked like a charm...