Executing a shell script

Shell Programming and Scripting
1 
 LD_LIBRARY_PATH=~/tme-0.8/bus/multibus:~/tme-0.8/bus/sbus:~/tme-0.8/dist/softfloat/softfloat/bits32:~/tme-0.8/dist/softfloat/softfloat/bits64:~/tme-0.8/generic:~/tme-0.8/host/bsd:~/tme-0.8/host/gtk:~/tme-0.8/host/posix:~/tme-0.8/ic:~/tme-0.8/ic/ieee754:~/tme-0.8/ic/m68k:~/tme-0.8/ic/sparc:~/tme-0.8/ic/stp22xx:~/tme-0.8/libltdl:~/tme-0.8/libtme:~/tme-0.8/libtme/host/x86:~/tme-0.8/machine/sun:~/tme-0.8/machine/sun2:~/tme-0.8/machine/sun3:~/tme-0.8/machine/sun4:~/tme-0.8/scsi:~/tme-0.8/serial:~/tme-0.8/tmesh 
export LD_LIBRARY_PATH

Executed by ./123.sh
But when I make a command => echo LD_LIBRARY_PATH or export the LD_LIBRARY_PATH variable is still unset. Any ideas why? Thanks Jack

2

Yup.

  1. you have to source the script
    or
  2. you have enter that from the command line

Environment variables created in a child process (running a script == child process)
are never visible to the parent process (your command line).

source means

.  myscript.sh

Note the leading "dot" separated by a space
or in bash

source myscript.sh