Exclude files in ls

Shell Programming and Scripting
1

Hi,

I need to exlucde the files which are present in exclude.txt from a directory

exlcude.txt
AUZ.txt
AUZ.chk
NZ.txt
NZ.chk

tried with below code but not working

 
ls -ltr | grep -v `cat exclude.lst`
2

Try

ls -ltr | grep -vFf exclude.txt
1 Like
3

Yeah the above on worked, will it be possible to exclude the files if i am having a file like below

exclude.txt

AUZ.txt AUZ.chk
NZ.txt NZ.chk
4

If you are using bash or ksh93 you could try:

ls -ltr | grep -vFf <(xargs -n1 < exclude.txt)
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5

yeah but would this same work if the file contains data with delimited separated

AUZ.txt,AUZ.chk,xyz
NZ.txt,NZ.chk,xxzz

This should exclude only

AUZ.txt
AUZ.chk
NZ.txt
NZ.chk
6

No, that would not, since the format of the file is one of the factors that determine the solution. If it keeps changing then the solution would need to change also. Please be clear about the format of the file and explain which part should be used, for example..

7

The file format can be like below

AUZ.txt,AUZ.chk,xyz
NZ.txt,NZ.chk,xxzz
8

And should the 3rd field be used, and if not, why not?

9

The third field will not be used only first two fields should only be used and those files need to be excluded while listing in directory

10

OK, try:

ls -ltr | grep -vFf <(cut -d, -f-2 exclude.txt | tr ',' '\n')

But please next time specify the correct format straight away in post #1

1 Like