gzip

Shell Programming and Scripting
1

Hi,

I want to gzip files in loop.

for i in `ls *.xml`;
do
gzip $i;
done

But i am gettin error like "/usr/bin/ls: Arg list too long"

Also please tell me how to do it with while loop and also using find and then exec.

2

try:

find . -name "*.xml" -exec gzip {} \;
3

Thanks a lot!!

In for loop i want to aviod this "argument list too long error".

How should i make it fetch 100 files at a time or may be one by one.

find . -name *.xml -exec gzip {} \;
It again gives the same error.
:slight_smile:

4

for each in $(find . -name "*.xml")
do
.....
done

Am not convinced!!!! :rolleyes:

5

Try it with xargs:

find . -name "*.xml" |xargs gzip

Regards

6

Yes Dennis ur rite, 'find' is working.
But still one problem is there, as there are already some zipped files in it.
So i having a continous prompt of overwrite.
"do you wish to overwrite (y or n)?"

How to overcome it and also how to run this loop in background.

7

For issue of prompting to overwrite,

Use gzip -f option

For running it in background, use & at the end..

ie,

find . -name "*.xml" -exec gzip -f {} \; &

or as Franklin suggested,

find . -name "*.xml" | xargs gzip -f &
8

Thanxx a lot to both of you Franclin and Dennis!!!

It worked......:slight_smile: