Hi,
I'm genrating a file from sql and the file looks like :
$value1=A
$value2=B
$value3=
$value4=
$value5=C
I want to delete those two lines which has Null after '='. Could you please guide me how to do it either using sed or awk ?
Hi,
I'm genrating a file from sql and the file looks like :
$value1=A
$value2=B
$value3=
$value4=
$value5=C
I want to delete those two lines which has Null after '='. Could you please guide me how to do it either using sed or awk ?
Try...
awk -F= '$2' infile
And a sed one.
sed /=$/d file
Great guys..thnx a lot..
Pure shell solution:
(04:25:18\[D@DeCoBox15)
[~]$ cat test
$value1=A
$value2=B
$value3=
$value4=
$value5=C
IFS="=";
while read test result; do
if [[ -n $result ]]; then
echo "$test=$result";
fi;
done < test
$value1=A
$value2=B
$value5=C
grep -v "=$" urfile
in the same script i'm also creaeting list files and i'm using the following command for that.
awk 'BEGIN {while (++i < ARGC) printf "%s\n", ARGV}' * > InfaFileList.lst
Since i can expect file names to contain space i'm using the above code. But the problem is the list file is getting created with directories name also, which i don't want. I just want to create file list containg the name of all the files not directories.
Could you please guide me?
use command basename,
for i in $(cat InfaFileList.lst)
do
basename $i
done
---------- Post updated at 10:03 AM ---------- Previous update was at 09:57 AM ----------
for i in $(cat InfaFileList.lst)
do
echo ${i##*/}
done
I think i was not able to explain my problem correctly. I have file names containing spaces and also few directories in the same location. I want ot create a file list with all file names(no dir name should be there).
Your code won't help in this case.
Try:
find . -name "*" -type f | sed 's!.*/!!g'