delete line upto the nth occurence of a particular charachter.

Shell Programming and Scripting
1

hi all

i want to delete a line upto a particular character. here is example.

cp cms/images/wifi-zone.png

i want to delete the line till . (cp cms/images/wifi-zone.) so the output wud be "png" only

how can i do it?

also please note down that dot (.) can also occur multiple times. so i need that delete the whole line till the occurrence of last dot (.) in the line.

e.g

input wud be...

cp cms/images/wifi-zone.css.php

and output wud be

php

Thanks in advance.

kashif

2 
# with shell:
$> A='cp cms/images/wifi-zone.css.php'
$> echo ${A##*.}
php
with sed:
$> echo 'cp cms/images/wifi-zone.css.php'| sed 's/.*\.\([^.]*\)$/\1/'
php

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3 
$sed 's/.*\.//g'
cp cms/images/wifi-zone.css.php
php

Entered input in Stdin in the above execution.

4

Thank You very much guys. both solutions are working fine. this is really awesome. Hats Off for you people.

5 
 echo 'cp cms/images/wifi-zone.css.php'| sed 's/.*\.//'

 echo 'cp cms/images/wifi-zone.css.php'| awk -F. '{print $NF}'

echo 'cp cms/images/wifi-zone.css.php'| grep -o '[^.]*$'
6

Thank You all. now i got the totally opposite scenario.

i need that keep the line till the occurrence of last slash (/) and delete anything after that.

e.g

input wud be...

cp cms/images/wifi-zone.css.php

and output wud be

cp cms/images/

Thanks in advance.

7

Solution 1

$ dirname "cp cms/images/wifi-zone.css.php"
cp cms/images

Solution 2

$ sed 's/\/[^\/]\+$//'
cp cms/images/wifi-zone.css.php
cp cms/images
8

You can use parameter expansion

# MYPATH=cms/images/wifi-zone.png
# echo ${MYPATH##*/}
wifi-zone.png
# echo ${MYPATH%/*}/
cms/images/

or use basename and dirname :cool:

9 
awk -F/ '{print $1"/"$2"/"}'
10

hi,

Thanks for the reply. its working fine. but just for more readability i dont want remove / at the end of line.
e.g

input wud be...

cp cms/images/wifi-zone.css.php

and output should be

cp cms/images/

currently out put using

sed 's/\/[^\/]\+$//'

is

cp cms/images

(/ is not there at the end).

so i just want to remove everything After slash (/) which will not include slash itself.

11

Should be something like:

sed 's!\(.*/\).*!\1!'

Regards

12 
sed 's/\/[^\/]\+$/\//'
13

Thank You All for Efforts and quick reply.