Cut on last backslash on hyperlink string-sed/awk??

Shell Programming and Scripting
1

hyper link- abc:8081/xyz/2.5.6/rtyp-2.5.6.jar

Needs to get "rtyp-2.5.6.jar" i.e character after last backslash "/"
how to do this using sed/awk??

help is highly appreciated.

2 
echo 'hyper link- abc:8081/xyz/2.5.6/rtyp-2.5.6.jar' | awk -F/ '{print $NF}'
3

thanks pravin u the master .
this site is excellent .hope i learn well from here.
once again thanks a ton

4

thanks pravin for quick & perfect reply. you genious.
hope i learn well more from this site.
once again hats off from a unix beginner :slight_smile:

---------- Post updated at 02:42 PM ---------- Previous update was at 02:40 PM ----------

btw: can we do this similar thing using sed?? will help me in directly replacing in the file.

5

sed

echo 'hyper link- abc:8081/xyz/2.5.6/rtyp-2.5.6.jar' |sed 's:.*/::g'

OR

p='hyper link- abc:8081/xyz/2.5.6/rtyp-2.5.6.jar'
echo ${p##*/}
6

Using split method (Ruby1.9+)

$ echo "abc:8081/xyz/2.5.6/rtyp-2.5.6.jar" | ruby -e 'puts gets.split("/")[-1]'
rtyp-2.5.6.jar

Using regex

$ echo "abc:8081/xyz/2.5.6/rtyp-2.5.6.jar" | ruby -e 'puts gets.gsub(/.*\//,"")'
rtyp-2.5.6.jar
7

wow! ruby also looks good.
one issue facing is i have to do this in a file.
whose content is like
file.txt>>

anb/xrg/zxczxc.java
admin/WEB-INF/struts-config.xml
h-t-t-p://abc:8081/xyz/2.5.6/rtyp-2.5.6.jar

**h-t-t-p stands for hyperlink .not allowed to post them as of now :frowning:

i need to cut only "http" lines with the jar names.
here its cutting all the lines & printing the last string after backslash.

8 
$ ruby -ne 'puts $_.gsub(/.*\//,"") if /http/' file
rtyp-2.5.6.jar

$ ruby -F'/' -ane 'puts $F[-1] if /http/' file
rtyp-2.5.6.jar

Put your code in code tags next time