Count occurences based on interval

Shell Programming and Scripting
1

Hi,

I have a file which has 4500 entries

10000
9880
9800
8700
8200
...
.....
...
...
...
...
...
...
...
50

What I need is for every one percentile count number of rows falling into that interval

output

10000-9900  1
9899-9800  2
9799-9700  0
so on...

Thanks,

2

Quick and dirty ..
Assuming ur input is in a file called t1
Paste the below in a file

#!/bin/ksh
sort -n t1|grep . > t2.tmp
maxval=`tail -1 t2.tmp`
count=0
endv=$maxval
let startv=$maxval/100
let startv=$startv*100
let endv=$startv+99
while test $endv -ge 99
do
cat t2.tmp|while read line
do
if test $line -ge $startv && test $line -le endv
   then
   let count=$count+1
fi
done
echo "${startv}"-"${endv}" "$count" >> Summary.txt
count=0
let startv=$startv-100
let endv=$endv-100
done

The output should be in Summary.txt