convert cpp program to c shell script ?

Hi guys
I tried to convert this c++ code to c shell script but there are some bugs and I don't know how to solve it.
This code prints the three variables in decreasing order:

int main()
{
int x,y,z;
cin >> x >> y >>z;

if ( x < y )
	if ( x < z )
		if ( y < z )
			cout << x <<"  " << y <<"  "<<  z << endl;
		else
			cout << x <<"  "<<  z <<"  "<<  y << endl;
	else
		cout << z <<"  "<< x <<"  "<< y << endl;
else
	if ( y < z )
		if ( x < z )
			cout << y <<"  "<< x <<"  "<< z << endl;
		else
			cout << y <<"  "<< z <<"  "<< x << endl;
	else
		cout << z <<"  "<< y <<"  "<<x << endl;

return 0;

}

Here is my try:

#!/bin/csh

if ( $1 < $2 ) then
	if ( $1 < $3 ) then
		if ( $2 < $3 ) then
			echo $1"  "$2"  "$3
		else
			echo $1"  "$3"  "$2
	else
		echo $3"  "$1"  "$2
else
	if ( $2 < $3 ) then
		if (  $1 < $3 ) then
			echo $2"  "$1"  "$3
		else
			echo $2"  "$3"  "$1
	else
		echo $3"  "$2"  "$1

I'm not familiar with csh but IMO the if statements must be closed with an endif:

if (expression) then
  ...
endif

or:

if (expression) then
  ...
else
  ...
endif

Regards

#!/bin/csh

if ( $1 < $2 ) then
	if ( $1 < $3 ) then
		if ( $2 < $3 ) then
			echo $1"  "$2"  "$3
		else
			echo $1"  "$3"  "$2
                          endif
	else
		echo $3"  "$1"  "$2
             endif
else
	if ( $2 < $3 ) then
		if (  $1 < $3 ) then
			echo $2"  "$1"  "$3
		else
			echo $2"  "$3"  "$1
                          endif
	else
		echo $3"  "$2"  "$1
             endif
endif