Comparing two variables

Shell Programming and Scripting
1

Script
#!/bin/sh
hardware=PC
os=WindowsNET
for i in `cat newservers`
do
x=`sudo /opt/openv/netbackup/bin/admincmd/bpplclients |grep $i |head -40 |grep $i|awk '{print $3;exit}'`
if [ "$i" -eq "$x" ]
then
echo "$i is already added"
else
echo "Need to add"
fi
done

O/p in debug mode

bash-2.05$ sh -x server_test.sh
hardware=PC
os=WindowsNET
+ cat newservers
+ sudo /opt/openv/netbackup/bin/admincmd/bpplclients
+ grep ds01smspsbby
+ head -40
+ awk {print $3;exit}
+ grep sun
x=sun
+ [ sun -eq sun]
sun is already added

+ sudo /opt/openv/netbackup/bin/admincmd/bpplclients
+ grep pluto
+ head -40
+ awk {print $3;exit}
+ grep pluto
x=
pluto is already added

for both conditions its showing the same output.Can soomeone correct this script?

2

Test operator -eq is only for integer comparisons. Try = instead.

3

Still didnt work..

4 
case $i in "$x") identical;; *) not;; esac