Is there a command (like ls -l) to get the file time stamp including seconds? The ls -l gives only the HH:MM, No SS
I don't have a C compiler to call stat()
I don't a command like stat too.
Please help.
As far as I know only GNU ls supports this
$ ls -l
total 488
-rw-r--r-- 1 me mygroup 234329 Aug 7 22:58 curl-7.15.5-2.el5.x86_64.rpm
-rw-r--r-- 1 me mygroup 253488 Aug 7 23:10 curl-7.16.4-1.fc8.x86_64.rpm
$ ls -l --full-time
total 488
-rw-r--r-- 1 me mygroup 234329 2007-08-07 22:58:11.000000000 -0400 curl-7.15.5-2.el5.x86_64.rpm
-rw-r--r-- 1 me mygroup 253488 2007-08-07 23:10:56.000000000 -0400 curl-7.16.4-1.fc8.x86_64.rpm
Cheers
ZB
I suppose, that is the precision in which the details are stored in the inode.
Even when you do a stat, HH : MM is the precision limit you get
Access: 2007-05-12 01:54:00.000000000
Modify: 2007-05-12 01:54:00.000000000
Change: 2007-05-12 01:54:00.000000000
Somebody might be knowing about this in detail 
ls -l --full-time is not working however. Is the precision configurable? I mean somewhere in the /etc ?
a perl one-liner:
$ touch file.now
$ perl -e '@d=localtime ((stat(shift))[9]); printf "%02d-%02d-%04d %02d:%02d:%02d\n", $d[3],$d[4]+1,$d[5]+1900,$d[2],$d[1],$d[0]' file.now
08-08-2007 10:20:36
$
That perl one liner (below) works perfectly. Can someone please explain what it is actually doing? I actually need the timestamp in this format:
yyyymmddhhmmss
perl -e '@d=localtime ((stat(shift))[9]); printf "%02d-%02d-%04d %02d:%02d:%02d\n", $d[3],$d[4]+1,$d[5]+1900,$d[2],$d[1],$d[0]' file.now 08-08-2007 10:20:36
I don't understand the significance of "08-08-2007 10:20:36" after the filename?
For informational purpose for AIX users
istat <filename>
returns following result
Inode 1784 on device 10/4 File
Protection: rw-r--r--
Owner: 0(root) Group: 0(system)
Link count: 1 Length 7240 bytes
Last updated: Thu Mar 6 18:49:23 IST 2008
Last modified: Thu Mar 6 18:49:23 IST 2008
Last accessed: Thu Mar 6 18:18:19 IST 2008
Formatting is a bit tough though than the perl solution, I think.
I also want to know the significance of "file.now 08-08-2007 10:20:36" in the perl script.. could u pls explain
hey.. i got it.. that is the output of that cmd.. :P.. but hw can we get it assigned to a variable???