Check if the input is number or text?

Shell Programming and Scripting
1

i have to check if is input number or text, i case that is text then exit script

exaple is hrere, but is not working

check_it()
{
    if [ "$1" != +([a-zA-Z]) ]
        then        
        if (( $1 > 0 && $1 < 13 )); 
            then
                echo "input number is ok"
        else
                echo "number not ok"
                exit 1
        fi
    else
      echo "just numbers please"
      exit 1
    fi
}

case $1 in
        0*)             echo "sorry, no leading zeroes"
                        exit 1;;
        "")             echo "input parameter is required"
                        exit 1;;
esac
2

Not sure what you were trying to achieve with both the check_it function and the case statement. You can do it all using a case statement as shown in the following example

#!/usr/bin/bash

shopt -s extglob

INPUT="123456"

case $INPUT in
   ( +([[:digit:]]) )   echo "INPUT is all numbers" ;;
   *)                   echo "INPUT is not all numbers" ;;
esac
3

users execute script like this:

/app/av/test/test.sh 12

in script i have 2 more script that will execute if the input parameter $1 is correct

first i must check if is $1 number and not text
second $1 must be number betwin 1-12, and cant have leading zeroes for number 1-9