Hi All,
I am using wget to call a url..i am getting 202 if it is successful. if not i am forcing the response code to 417.
how can i capture the response code and print 0 if it is 202 and 1 if it is not 202
any ideas, please share
Thanks,
Jack.
Hi All,
I am using wget to call a url..i am getting 202 if it is successful. if not i am forcing the response code to 417.
how can i capture the response code and print 0 if it is 202 and 1 if it is not 202
any ideas, please share
Thanks,
Jack.
(($?==202))
will return 0 if $? is 202
You'll want the --server-response
option, eg
wget --server-response http://localhost/nx.file 2>&1 | awk '/^ HTTP/{print $2}'