Hi,
I need an awk command that would parse the below expression
Input Format
1 'Stmt1 ............................'2 'Stmt2 ............................'3 'Stmt3 ............................'4 'Stmt4 ............................'5 'Stmt5 ............................'6 'Stmt6 ............................'7 'Stmt7 ............................'8 'Stmt8 ............................'9 'Stmt9 ............................'10 'Stmt10 ............................'11 'Stmt11 ............................'12 'Stmt12 ............................'13 'Stmt13 ............................'
Desired Output
'Stmt1 ............................'
'Stmt2 ............................'
'Stmt3 ............................'
'Stmt4 ............................'
'Stmt5 ............................'
'Stmt6 ............................'
'Stmt7 ............................'
'Stmt8 ............................'
'Stmt9 ............................'
'Stmt10 ............................'
'Stmt11 ............................'
'Stmt12 ............................'
'Stmt13 ............................'
1) It must look for all words between consecutive numbers
2) The statement / expression may contain special characters like $,white space,TAB,colon etc. The command must omit those
3)However the statement will not have any numbers
4) The next number that marks the begin of new statement will be increment the previous by 1
5) Like in the above example all statements may not start with ' character or end with a ....' pattern
Thanks and Best Regards,
Rajan.S