awk/input parameter

Shell Programming and Scripting
1

Hi,

My script takes in one input parameter($1-email id) on the command line...

The script contains something like this...

awk '$1 == 400' abc.log >def.log
mail -s subject $1 <def.log

abc.log looks something like this...

300 222 330 123 445
400 098 890 727 663

How do i make the awk to know that by $1 I am referring to the first field in the log rather than the input parameter($1) given in the command line..

2 
var=400
awk -v v1=$var '{ if ( $1 == v1 ) { print } }' filename
3

Thanks Madhan...

What if the script takes in two input parameters..it becomes tricky then eh?

First parameter-$1-email
Second parameter- $2 -number(eg: 400 ,300)

awk '$1 == $2' abc.log >def.log
mail -s subject $1 <def.log

abc.log looks something like this...

300 222 330 123 445
400 098 890 727 663

4

just extend the variable list to the number of variables that are in question

var=400
var2=890
awk -v v1=$var -v v2=$var2 '{ if ( $1 == v1 && $3 == v2 ) { print } }' filename