Hi,
I would like to get 5th field from this output using FS[ %].
Filesystem 1024-blocks Used Available Capacity Mounted on
172.29.138.222:/vol/vol0 311936256 2565248 309371008 1% /tmp/test
My command is
df -kP | awk ' BEGIN { FS="[ %]" ; } { print $5 ; } '
For some reason it keeps return blank screen.
Would someone help me on this ?
Thanks.
nj78
2
Does this work for you?
df -kP | awk '{print "["" "$5"]" ;}'
matt.d
3
I think you are getting that because the % is not the delimiter for every field.
If I do
df -kP | awk '{print $5}'
I get all the capacities. What output are you looking for?
Hi,
I am expecting the output to eliminate %. That's why I place % as one of my field separator.
Thanks for the input though.
Hi,
We found something on google, and it works
df -kP | awk ' BEGIN { FS="[ %\t]+" ; } { print $5 ; } '
Or you could simply use
df -kP | awk '{ print $5 ; } ' | sed 's/%//'
as well