my desired output is like this:
so the thing is, I only need to show every of this part out
but the frequency of that data is not fixed, so sometimes it may have 4 lines, or 6 lines or whatever in that file. However, the last line will always have empty space/line below it.
What's a good criterion for identifying those lines?
grep xxxx file
pass your output result to sed
sed 's/^ *//'
they are one single word, but may not be similiar
huh? i don't get your meaning
cat file | grep xxx | awk -F"*" '{ print $2 }'
Useless Use of Cat! Useless Use of Grep | Awk!
awk -F "*" '/xxx/ { print $2 }' file
I don't think that does what was requested, though. I'm not sure, however; it would still help to get a sample of the expected output.
the best....
awk: syntax error near line 1
awk: bailing out near line 1
bump need help
Don't bump your question, forum rules
Vsl Voy Port Sz Cat Wt Block Slot Row Qty Crane OperCode ResvFor
carrier name 6113A xxxx 40 GP M U02 25 8 1 0
*some space* xxxx 40 HC M U02 25 8 1 0
*some space* xxxx 40 HC H U02 25 7 3 0
Please redefine your data sample.
i can't do more than one spacing, but there are five spacing between the first word and the 0th position
Try this:
awk '/xxxx/{p="xxxx";print substr($0,index($0,p),length($0)+1-index($0,p))}' data.file