awk regular expression search

Shell Programming and Scripting
1

Hi All,

I would like to search a regular expression by passing as an i/p variableto AWK.

For Example ::

162.111.101.209.9516 
162.111.101.209.41891
162.111.101.209.9516 
162.111.101.209.9517 
162.111.101.209.41918
162.111.101.209.9517 
162.111.101.209.41937
162.111.101.209.41951
162.111.101.209.41954

i would like to extract 9516 and 9517 i.e., pattern 951[1-9] only.

Below is the command i have tried which worked

cat File | awk -F. ' $NF ~ /951[1-9]/ {print $0 }'

But i would like to pass the search pattern as a variable. Can you please help me.

2 
awk -F. '$NF ~ p' p='951[1-9]' infile
3

im working on netstat command.
can you please help me how to stream the output to above command

4

netstat 's output includes both local and foreign address, which one do you want?

5

local address

6

If the local address is in the first column (as on Solaris),
something like this might work:

netstat -anf inet | nawk '$1 ~ p' p='\.951[1-9]$'

If the above script errors out or doesn't produce the expected output,
post a sample of your netstat output.
What OS are you using?

7

yes it is working. Thanks.
How about if i want to pass a variable instead of 951[1-9]

8 
var='\\.152[1-9]$'
netstat -anf inet | nawk '$1 ~ p' p="$var"