awk if statement matching all lines starting w/ a number

Shell Programming and Scripting
1

Does awk have a syntax for a range of numbers or is this the best way?

 if ($1 >= 0 && $1 <= 9 )
2

Hi.

Awk uses regular expressions.

You could say

$1 ~ /^[0-9]$/ { ... }

or

if ( $1 ~ /^[0-9]$/ ) ....
3

exactly what I was looking for "proper syntax is such sweet sorrow". Thank you and congrats on Switzerland qualifying for the 2010 world cpu today !!

4

Hopp Schwiiz!

5

Usa usa usa !

6

/^[0-9].*/

7

n1djs thank you for your valuable input, its help me get further today, seems its one thing after another hoping to hit jack pot soon. Will post when I am done. Again thanks

8

Finally hit the jack pot. again thank you for your contribution which help me move forward along to my destination:

{
if (sub(/DISCOVERY=ON/, "DISCOVERY=OFF"))
print $0
if ( $1 ~ /^#/ ) {
        print $0 }
if ( NF == 4 ){
    if ( system("test -d " $4) ) {
         }
    else {
        print "1        0       0       "$4 "\n" }
}
}

---------- Post updated at 06:03 PM ---------- Previous update was at 05:29 PM ----------

n1djs & scottn finally hit the jack pot. Again thank you for your contribution which help me move forward along to my destination:

{
if (sub(/DISCOVERY=ON/, "DISCOVERY=OFF"))
   print $0
if ( $1 ~ /^#/ ) {
   print $0 }
if ( NF == 4 ){
   if ( system("test -d " $4) ) {
         }
   else {
        print "1        0       0       "$4 "\n" }
}
}