Hi guys
i need you help its urgent..
im trying to translate this file processing command in Perl.
awk -F'|' '{ print $5 }'
any ideas
Regards
Hi guys
i need you help its urgent..
im trying to translate this file processing command in Perl.
awk -F'|' '{ print $5 }'
any ideas
Regards
hello,
try,split() in perl and then grab $arr[5].
perl -wln -e 'my @arr=split("|",$_);print $arr[5];' file1 file2 ...
Regards,
Gaurav.
Thanks man
it not working...
here is a smaple of my log :
2010-07-12 00:33:52|Raid-bridge|5492645293293831725|HTTP|Get|File allowed|x.x.x.x|
if i run :
awk -F'|' '{ print $5 }' log
the results is :Get
however if i run :
perl -wln -e 'my @arr=split("|",$_);print $arr[5];'
results: 0
Thanks
regards
Raid
That's because Perl, contrary to awk, starts indexing its fields at 0. This should work:
perl -ple '@a = split /\|/; $_ = $a[4];' log
Works great
Thanks guys
i have an exam for linux and i just cannot understand when i should use print $5 or $6.
i need to find the month and the date so somebody use print $5 somebody print 6 and i am confused.
thanks..
perl -F'\|' -lape '$_=$F[4]'
---------- Post updated at 06:44 PM ---------- Previous update was at 06:42 PM ----------
Nevermind, I just noticed that the problem was addressed about 3 weeks ago.