awk & date time format

Shell Programming and Scripting
1

This gives:

grep "qprt  -o -dp -N 1 -P" printfile.log.1216 |awk '{print $7, $9}' |grep lpc1z

The output like below:

lpc1z /cerner/d_prod/print/ccltemp4235396d030a.dat.tmp.1216075330]
lpc1z /cerner/d_prod/print/ccltemp4235396d036a.dat.tmp.1216075634]
lpc1z /cerner/d_prod/print/ccltemp4235396d038a.dat.tmp.1216075721]
lpc1z /cerner/d_prod/print/ccltemp4235396d056a.dat.tmp.1216080939]

What I am trying to do is:

grep "qprt  -o -dp -N 1 -P" printfile.log.1216 |awk '{print $7, $9}' |grep lpc1z |awk '{print $1, and_something_for_date_time}'

1216075330 is the timestamp, 12-16 07:53:30

so that, it can give me:

lpc1z  12-16 07:53:30
lpc1z  12-16 07:56:34
lpc1z  12-16 07:57:21

Please advise

2 
 
grep "qprt -o -dp -N 1 -P" printfile.log.1216 |awk '{print $7, $9}' |grep lpc1z | sed 's#^\([^ ]*\).*\.\(..\)\(..\)\(..\)\(..\)\(..\)]$#\1 \2-\3 \4:\5:\6#'
3

Thank you so much. That works fine!!