$OPTARG changes commandline input

Shell Programming and Scripting
1

Hi there,

I hope, that I do not open an thread, that is already existing, but I didn't found something matching with my problem while searching for problems with "getopts"

My problem ist, that I'm taking arguments from commandline into my script with getopts, I've an flag -s, after that there comes an path to an *.sql File.
e.g. script.sh -s /batch/alpha/database/create_db.sql

This is no problem, but I want to have it more save, want, that the custumer must exactly hit ONE file, even, if he/she is using joker like *.

Therefore I wanted to count the hits, and if there is more than 1 hit, the script should terminate.

But if I type for example: ./script.sh -s /test/test*.sql and in the directory are the files "test.sql" and "test1.sql" I will not find the term "/test/test*.sql" in $OPTARG but "/test/test1.sql" !!!

Is there any chance, perhaps some kind of quoting, that I can get what I typed in on the commandline?? Only then I could check, if the term produces more than one matchings.

Thank you for the help and excuse my worse English, as I'm coming from Germany.

So long,

Thomas

2

Hello,

You can get count of command line arguments using $# variable. Sample code

if [ $# -gt 1 ]
then
 echo "Only one argument can be provided to $0" ;
 exit 1 ;
else
 #your desired coding
 echo "Continue" ;
fi

-Nithin.

3

I'm afraid, that you don't understand my problem right now.

I'm reading many arguments with getopts from the commandline. Many of them are optional. My problem is, that I'm reading an argument, that includes an absolute path, as "/test/test*.sql". When I read the argument from $OPTARG, I found the joker "*" substituted with the first file, that matches, for example, "/test/test1.sql", but I need the non substituted argument, so that I can use the input.

So if I had a variable with "/test/test*.sql" I could do the following:

e.g.:

var_path="/test/test*.sql"

var_file_matches=`ls $var_path | wc -l`
if [ $var_file_matches -gt 1 ]
then
       echo "More than one match with you argument, BREAK!"
       exit 99
fi

.
.
.
other programmcode

This is the part in my script, reading arguments from the shell:

#! /usr/bin/ksh
.
.
.

while getopts ":rRvVHhk:K:FfQ:q:D:d:Z:z:s:S:p:P:cC" arg # Variablen einlesen 
   do 
        case $arg in 
        q|Q) 
                QUELL_PFAD="$OPTARG" 
                ;; 
        d|D) 
                QUELL_DATEI="$OPTARG" 
                ;; 
        k|K) 
                KONFIG_PFAD="$OPTARG" 
                ;; 
        s|S) 
                SQL_PFAD="$OPTARG" 
                ;; 
        p|P) 
                PARAMETER="$OPTARG" 
                ;; 
        z|Z) 
                ZIEL_PFAD="$OPTARG" 
                ;; 
        c|C) 
                COMPRESS_FLAG=1 
                ;; 
        h|H) 
                usage 
                exit_log 0 
                ;; 
        v|V) 
                version 
                exit_log 0 
                ;; 
        f|F) 
                FORCIERE_NEU_DIR=1 
                ;; 
        r|R) 
                REKURSIV_FLAG=1 
                ;; 
        *) 
                para_fehler 
                ;; 
        esac 
   done 
shift